The horizontal distance between AC is 15 units
The vertical distance between AC is 7 units
The point B is located such that AB: BC = 5:2, in other words, AB = 5/7 of the line and BC is 2/7 of the line
5/7 of the horizontal distance is (5/7) × 15 = 75/7
2/7 of the vertical distance is (2/7) × 15 = 30/7
The coordinate of B is (75/7, 30/7)