Respuesta :
x^2-16 is a difference of squares of the form:
(a^2-b^2) which always factors to:
(a+b)(a-b), in this case we have:
(x+4)(x-4), we are told that width is (x+4) so the length is:
(x-4)
(a^2-b^2) which always factors to:
(a+b)(a-b), in this case we have:
(x+4)(x-4), we are told that width is (x+4) so the length is:
(x-4)
Hello Mate!
[tex]Area=LW[/tex]
[tex]x^2-16=L(x+4)[/tex]
Remember difference of 2 perfect squares to factor [tex]x^2-16[/tex]
[tex](x-4)(x+4)=L(x+4)[/tex]
Divide both sides by [tex](x+4)[/tex]
[tex]x-4=L[/tex]
Therefore, [tex]length=x-4[/tex]
I Hope my answer has come to your Help. Thank you for posting your question here in [tex]Brainly[/tex]. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
[tex](Ps. Mark As Brainliest IF Helped!)[/tex]
[tex]-TheOneAboveAll :D[/tex]
[tex]Area=LW[/tex]
[tex]x^2-16=L(x+4)[/tex]
Remember difference of 2 perfect squares to factor [tex]x^2-16[/tex]
[tex](x-4)(x+4)=L(x+4)[/tex]
Divide both sides by [tex](x+4)[/tex]
[tex]x-4=L[/tex]
Therefore, [tex]length=x-4[/tex]
I Hope my answer has come to your Help. Thank you for posting your question here in [tex]Brainly[/tex]. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
[tex](Ps. Mark As Brainliest IF Helped!)[/tex]
[tex]-TheOneAboveAll :D[/tex]