Respuesta :
(Look at the attached graphic)
Years = log (3,000 / 150) / 12 * log (1 + .025 / 12)
Years = log (20) / 12 * log ( 1.0020833333 )
Years = 1.3010299957 / 12 * .0009038389838
Years = 1.3010299957 / 0.0108460678
Years = 119.954
That's a LONG time
Years = log (3,000 / 150) / 12 * log (1 + .025 / 12)
Years = log (20) / 12 * log ( 1.0020833333 )
Years = 1.3010299957 / 12 * .0009038389838
Years = 1.3010299957 / 0.0108460678
Years = 119.954
That's a LONG time

Answer:
The time is 119.973 years.
Step-by-step explanation:
In the starting, we put $150, to accumulate to $3,000 so that we can put a down payment on our car.
An interest rate of 2.5% compounded monthly.
So, we earn [tex]2.5/12[/tex] = 0.2083% per month.
Appying the formula : [tex]A=P(1+r/n)^{nt}[/tex]
Now at time 't' (in months), the total amount will be [tex]150(1.002083)^{t}[/tex]
Given is that you need to get $3000 at the end of t years.
So, the equation becomes:
[tex]150(1.002083)^{t}=3000[/tex]
=> [tex](1.002083)^{t}=20[/tex]
Taking log on both sides,
ln[tex](1.002083^{t})[/tex] = ln(20)
[tex]t=ln(20)/ln(1.002083)[/tex]
t = 1439.68 months
or [tex]1439.68/12=119.973[/tex] years
Note: This value of years is unrealistic.