Answer:
The magnitude of the given vector is [tex]\sqrt{29}[/tex].
Step-by-step explanation:
The magnitude of a vector v=<a,b> is defined as
[tex]|v|=\sqrt{a^2+b^2}[/tex]
The given vector is
[tex]v=<5,-2>[/tex]
The magnitude of the given vector is
[tex]|v|=\sqrt{5^2+(-2)^2}[/tex]
[tex]|v|=\sqrt{25+4}[/tex]
[tex]|v|=\sqrt{29}[/tex]
Therefore the magnitude of the given vector is [tex]\sqrt{29}[/tex].
