Calculate the ratio of H+ ions to OH– ions at a pH = 7. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide. Then divide the H+ concentration by the OH– concentration. Record this calculated ratio in Table A of your Student Guide. Compare your approximated and calculated ratios of H+ ions to OH– ions at a pH = 7. Are they the same? Why or why not? Record your comparison in Table A. What is the concentration of H+ ions at a pH = 7? mol/L What is the concentration of OH– ions at a pH = 7? mol/L What is the ratio

Respuesta :

You must know the concept of pH of a solution and its relation to the concentration of H+ and OH- ions. pH is a measure of the substance's acidity or basicity. From the definition of Arrhenius, an acid contains an H+ while a base contains a OH- ion. From this definition, we can say that an acidic substance has a higher concentration of H+ ions. Now, I'll introduce here that pH is the value of the negative logarithm of the concentration of H+. In equation,

pH = -log[H+]

The term pOH is therefore also, pOH = -log[OH-]. Therefore, the relationship that connects the two negative logarithms is:

pH + pOH = 14

The pH scale starts from 1 being the most acidic to 14 being the most basic. The neutral pH is 7. Thus, for a pH of 7, the H+ and the OH- concentrations are equal. 

pH = 7 = -log[H+]
[H+] = 1×10⁻⁷ mol/L = [OH-]

Since the concentrations are equal, the ratio is equal to 1.

The ratio of hydrogen to hydroxide ion at pH 7 is 1.

We know that pH is defined as the negative logarithm of hydrogen ion concentration.

[H^+] = Antilog(-7) = 1 × 10^-7 M

But [H^+] [OH^-] = 1 × 10^-14 M

[OH^-] =  1 × 10^-14 M/1 × 10^-7 M

[OH^-] =  1 × 10^-7 M

Hence;

[H^+] / [OH^-] =  1 × 10^-7 M/ 1 × 10^-7 M = 1

The ratio of hydrogen to hydroxide ion at pH 7 is 1.

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