Respuesta :
f(x) = 4.(3)ˣ. This is the growth of a dragonfly population i ONE year.
4 is a constant and 3 is the growth pattern over ONE year, then we can write it:
f(x) = 4.(3¹)ˣ , where the exponent 1 (on 3) represents the cycle of growth with is ( once a year).
Now if we want to calculate the growth 4 times a year, then the equation becomes:
f(x) = 4.[3^(1/4)]ˣ
f(x) = 4[1.3160]ˣ OR rounding up f(x) = 4.(1.32)ˣ with a growth rate of 32%
4 is a constant and 3 is the growth pattern over ONE year, then we can write it:
f(x) = 4.(3¹)ˣ , where the exponent 1 (on 3) represents the cycle of growth with is ( once a year).
Now if we want to calculate the growth 4 times a year, then the equation becomes:
f(x) = 4.[3^(1/4)]ˣ
f(x) = 4[1.3160]ˣ OR rounding up f(x) = 4.(1.32)ˣ with a growth rate of 32%
The correct function for Erin's purpose is [tex]\bold{f(x) = 4(1.32)^{4x}}[/tex] and the new growth rate is 32%
What is exponential growth?
" In exponential growth a value increases in proportion to its current value. Such as always doubling."
Exponential growth equation:
[tex]f(x) = a(1 + r)^{t}[/tex]
where a is the initial value
r is the growth rate
t is the time
For given example,
The function [tex]f(x) = 4(3)^x[/tex] represents the growth of a dragonfly population every year in a remote swamp.
Erin wants to manipulate the formula to an equivalent form that calculates four times a year, not just once a year.
So the function becomes,
[tex]\Rightarrow f(x) = 4(3^{\frac{1}{4} })^{4x}\\\\\Rightarrow f(x) = 4(1.316)^{4x}\\\\\Rightarrow f(x) = 4(1+0.316)^{4x}\\[/tex]
By comparing above function with exponential growth function we have,
⇒ 1 + r = 1 + 0.316
⇒ r = 0.316
⇒ r ≈ 0.32
The percentage growth rate is,
⇒ r = 32%
Therefore, the correct function is [tex]\bold{f(x) = 4(1.32)^{4x}}[/tex] with the new growth rate of 32%
Learn more about the growth rate here:
https://brainly.com/question/9883435
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