Let f(x) = 8x^3 − 22x^2 − 4 and g(x) = 4x − 3. Find f(x) over g(x).

A. 2x^2 − 4x − 3 − 13 over (4x - 3)
B. 2x^2 − 4x − 3 − (the quantity of 4 x - 3 over 13)
C. 2x^2 − 7x − 1
D. 2x^2 − 7x − 5 + (the quantity of x - 4 over 4 x - 3)

Respuesta :

You would use the long division technique..

Here it looks like:

            --------------------
4x − 3 |
8x^3 − 22x^2 − 4
---------
           |

           |
           |

and like that,,,

after you do this, you will get

[tex]2x^2-4x-3-\frac{13}{4x-3}[/tex]


hope that helps