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A clear plastic paperweight with an unknown index of refraction rests on your desk as shown in the figure. A ray of light enters the top of the paper weight with a 79.0° angle of incidence and undergoes total internal reflection (TIR) at the right side of the paperweight. (a) Determine the minimum value for the index of refraction of the plastic for which TIR will occur.

Respuesta :

Jayx2007

To find the minimum value for the index of refraction (n) of the plastic for which total internal reflection (TIR) will occur, we use the critical angle formula:

The critical angle (θc) is given by:

θc = arcsin(n2/n1)

Given:

Angle of incidence, θ1 = 79.0 degrees

Refractive index of air, n1 = 1

We need to find n2.

Using the critical angle formula:

θc = arcsin(n2/1) = 79.0 degrees

Thus,

n2 = sin(79.0 degrees)

We calculate n2 to find the minimum index of refraction of the plastic for TIR to occur.

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