To determine the number of grams in 0.25 moles of KMnO4 (potassium permanganate), we need to use the molar mass of KMnO4, which is the sum of the atomic masses of each element in the compound.
The molecular formula of potassium permanganate (KMnO4) consists of:
- 1 potassium (K) atom
- 1 manganese (Mn) atom
- 4 oxygen (O) atoms
Now, let's find the molar mass of KMnO4:
- Atomic mass of potassium (K) = 39.10 g/mol
- Atomic mass of manganese (Mn) = 54.94 g/mol
- Atomic mass of oxygen (O) = 16.00 g/mol
Molar mass of KMnO4:
= (1 * 39.10 g/mol) + (1 * 54.94 g/mol) + (4 * 16.00 g/mol)
= 39.10 g/mol + 54.94 g/mol + 64.00 g/mol
= 158.04 g/mol
Now, we'll use the molar mass to convert moles to grams:
- 0.25 moles * (158.04 g/mol) = 39.51 grams
Therefore, there are 39.51 grams in 0.25 moles of KMnO4.
