Answer:
[tex]\\9x^2+x+\dfrac{1}{36}\\\\=(3x)^2+2.(3x).\dfrac{1}{6}+\biggl(\dfrac{1}{6}\biggl)^2\\\\=\biggl(3x+\dfrac{1}{6}\biggl)^2\ \ \ \ [a^2+2ab+b^2=(a+b)^2][/tex]
x = -1/18
Step-by-step explanation:
