In the diagram, A, B, C, and D are on the circle and O is the midpoint of the circle. DO is produced to A such that DO OA. B = 32°. ​

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Answer:

It seems like you're describing a geometry problem involving a circle and some points A, B, C, and D. Can you provide more details or clarify what you'd like assistance with?

Step-by-step explanation:

1. **Given information**:

- Point B is located on the circle.

- Angle B = 32°.

- DO is produced to A such that DO = OA.

2. **Understanding the scenario**:

- Since DO is produced to A such that DO = OA, it implies that the radius of the circle is equal to the line segment DO.

3. **Drawing the situation**:

- Draw a circle with center O.

- Place point B on the circle.

- Draw a line segment from point O to point B to represent the radius of the circle.

- Label angle B = 32°.

4. **Analyzing the problem**:

- We know that in a circle, the angle subtended by an arc at the center is double the angle subtended by it at any point on the circumference.

- In other words, angle at the center is twice the angle at the circumference subtended by the same arc.

- So, angle B = 32° means that the angle subtended by arc AB at the center O is 64°.

5. **Finding the unknown**:

- Now, since DO is produced to A such that DO = OA, it means that angle AOD is a straight angle (180°), and angle AOB = 360° - 64° (since the sum of angles in a circle is 360°).

- So, angle AOB = 296°.

6. **Final step**:

- We have now found angle AOB = 296°.