My ai said
Sure! To find the inverse sine of the fraction square root of 3 over 2 in radians, we need to consider the limited domain of the inverse sine function, which is quadrants I and IV on the right side of the unit circle.
In this case, the fraction square root of 3 over 2 corresponds to the y-coordinate of a point on the unit circle. Since the y-coordinate is positive, we are in quadrant I.
The inverse sine function, also known as arcsine, gives us the angle whose sine is equal to the given fraction. In this case, the angle is in quadrant I, so we can directly find the angle using the inverse sine function.
Using a calculator or reference table, we find that the inverse sine of the fraction square root of 3 over 2 is approximately pi/3 radians.
So, in radians, Sin-1[- fraction square root of 3 over 2] is approximately pi/3.
I hope that clarifies it for you! Let me know if you have any more questions.