A large ship is being towed by two tugs. The larger tug exerts a force which is 30 percent greater than the smaller tug, and at an angle of 25 degrees north of east.

Which direction must the smaller tug pull to ensure that the ship travels due east?

It should pull at an angle of

Respuesta :

Answer:

  33.3° south of east

Step-by-step explanation:

You want the angle a smaller tug must pull if a larger tug with 30% greater force is pulling 25° north of east and the desired resultant is due east.

Net force

The net force in the northerly direction must be zero.

The northerly component of the force from the larger tug is ...

  1.3·sin(25°)

We want that to be the opposite of the northerly component from the smaller tug:

  1.3·sin(25°) +1.0·sin(x°) = 0

  sin(x°) = -1.3sin(25°)

  x° = arcsin(-1.3·sin(25°)) ≈ -33.3°

The smaller tug must pull at an angle of 33.3° south of east.

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