Respuesta :
Answer:
-1
Explanation:
To determine the oxidation number for the compound KMnO₄– (potassium permanganate), we can break it down into its individual elements:
1. K (Potassium): The oxidation number of Group 1 elements like potassium is typically +1.
2. Mn (Manganese): To find the oxidation number of manganese in KMnO₄–, we need to consider the overall charge of the compound, which is –1. The sum of oxidation numbers in a compound is equal to the overall charge. Let the oxidation number of manganese be x.
The oxidation number of potassium is +1, and there is one potassium atom in KMnO₄–. The total oxidation number contribution from potassium is +1.
The oxidation number of oxygen is usually –2, and there are four oxygen atoms in KMnO₄–. The total oxidation number contribution from oxygen is 4(-2) = -8.
Putting it all together: +1 + x - 8 = -1
x - 7 = -1
x = -1 + 7
x = +6
Therefore, the oxidation number of manganese in KMnO₄– is +6.
3. O (Oxygen): As mentioned earlier, the oxidation number of oxygen is typically -2 in most compounds.
Therefore, in KMnO₄–:
- The oxidation number of K is +1.
- The oxidation number of Mn is +6.
- The oxidation number of O is -2.
So, the oxidation number for KMnO₄– is +1 (K) + 6 (Mn) + 4(-2) (O) = -1.
