Answer:
84 g
Step-by-step explanation:
You want the mass of zinc in a chemical containing 231 g of copper if the ratio of zinc to copper is 4 to 11.
The given proportion is ...
Zn/Cu = 4/11 = Zn/(231 g)
Multiplying by 231 g, we find ...
Zn = (231 g)(4/11) = 84 g
The chemical contains 84 g of zinc.