Answer:
MARK ME AS BRAINLIEST
Explanation:
Here's how to calculate the volume of sulfur dioxide gas produced:
1. **Balanced Chemical Equation:** The provided equation (S O2 → SO2) is already balanced, which is good. This means for every 1 mole of sulfur (S), 1 mole of sulfur dioxide (SO2) is produced.
2. **Moles of Sulfur:**
* We are given the mass of sulfur (m) as 600g.
* We need to convert this mass to moles (n) using the molar mass (M) of sulfur.
* M (sulfur) = 32.06 g/mol (you can find this in a periodic table).
* n (sulfur) = m (sulfur) / M (sulfur)
* n (sulfur) = 600g / 32.06 g/mol
* n (sulfur) ≈ 18.72 mol (rounded to two decimal places)
3. **Moles of Sulfur Dioxide:**
* Since the chemical equation tells us a 1:1 ratio between sulfur and sulfur dioxide, the number of moles of sulfur dioxide produced is equal to the moles of sulfur reacted.
* n (sulfur dioxide) = n (sulfur) = 18.72 mol
4. **Volume of Sulfur Dioxide:**
* We are given that the molar volume of a gas at room temperature and pressure (rtp) is 24 dm³/mol.
* We can use this to convert moles of sulfur dioxide to volume.
* Volume (SO2) = n (SO2) * Molar volume (gas at rtp)
* Volume (SO2) = 18.72 mol * 24 dm³/mol (convert dm³ to cm³ by multiplying by 1000)
* Volume (SO2) ≈ 44928 cm³ (rounded to the nearest whole number)
Therefore, burning 600g of sulfur would produce approximately 44,928 cm³ of sulfur dioxide gas at room temperature and pressure.
