Respuesta :
Answer: The chemical equation for the given reaction is written below.
Explanation:
The reaction between sodium phosphate and lithium sulfate is possible and it results in the formation of a white colored precipitate.
The chemical equation for the reaction of lithium sulfate and sodium phosphate follows:
[tex]2Na_3PO_4(aq.)+3Li_2SO_4(aq.)\rightarrow 2Li_3PO_4(s)+3Na_2SO_4(aq.)[/tex]
By Stoichiometry of the reaction:
2 moles of sodium phosphate reacts with 3 moles of lithium sulfate to produce 2 moles of lithium sulfate salt (white in color) and 3 moles of sodium sulfate.
Hence, the balanced chemical equation is written above.
The balanced chemical equation is as follows:
[tex]\boxed{{\text{2N}}{{\text{a}}_{\text{3}}}{\text{P}}{{\text{O}}_4}\left( {aq} \right) + 3{\text{L}}{{\text{i}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\left( {{\text{aq}}} \right) \to 2{\text{L}}{{\text{i}}_{\text{3}}}{\text{P}}{{\text{O}}_4}\left( s \right) + 3{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left( {aq} \right)}[/tex]
Further Explanation:
The chemical reaction must be a balanced chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side so that it follows the Law of the conservation of mass.
Double displacement reaction is defined as the reaction in which ions of two compounds interchange with each other to form the product. For example, the general double displacement reaction between two compounds is as follows:
[tex]{\text{AX}} + {\text{BY}} \to {\text{AY}} + {\text{BX}}[/tex]
The steps to balance a chemical reaction are as follows:
Step1: Complete the reaction and write the unbalanced symbol equation.
[tex]{\text{N}}{{\text{a}}_{\text{3}}}{\text{P}}{{\text{O}}_4}[/tex] reacts with [tex]{\text{L}}{{\text{i}}_{\text{2}}}{\text{S}}{{\text{O}}_4}[/tex] to form [tex]{\text{L}}{{\text{i}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}[/tex] and [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex]. The physical state of both the reactants is aqueous and [tex]{\text{L}}{{\text{i}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}[/tex] is solid and [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] is aqueous. This reaction is double displacement reaction. The unbalanced chemical equation is as follows:[tex]{\text{N}}{{\text{a}}_{\text{3}}}{\text{P}}{{\text{O}}_4}\left( {aq} \right) + {\text{L}}{{\text{i}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\left( {{\text{aq}}} \right) \to {\text{L}}{{\text{i}}_{\text{3}}}{\text{P}}{{\text{O}}_4}\left( s \right) + {\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left( {aq} \right)[/tex]
Step2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.
On reactant side,
Number of sodium (Na) atom is 3.
Number of phosphorus (P) atom is 1.
Number of oxygen (O) atom is 8.
Number of lithium (Li) atom is 2.
Number of sulphur (S) atom is 1.
On product side,
Number of sodium (Na) atom is 2.
Number of phosphorus (P) atom is 1.
Number of oxygen (O) atom is 8.
Number of lithium (Li) atom is 3.
Number of sulphur (S) atom is 1.
Step3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on either side, so here we balance first the number of sodium and lithium atoms on either side.
To balance the number of sodium atoms on either side we multiply [tex]{\text{N}}{{\text{a}}_{\text{3}}}{\text{P}}{{\text{O}}_4}[/tex] by 2 on reactant side and [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] 3 on product side. Similarly to balance number of lithium atoms on either side we multiply [tex]{\text{L}}{{\text{i}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}[/tex] by 3 on reactant side and [tex]{\text{L}}{{\text{i}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}[/tex] 2 on product side.This gives,
[tex]\boxed{\text{2}}{\text{N}}{{\text{a}}_{\text{3}}}{\text{P}}{{\text{O}}_4}\left( {aq} \right) + \boxed3{\text{L}}{{\text{i}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\left( {aq} \right) \to \boxed2{\text{L}}{{\text{i}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}\left( s \right){\text{ + }}\boxed{\text{3}}{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\left( {aq} \right)[/tex]
Step 6: So, the balanced chemical equation is given as follows:
[tex]{\text{2N}}{{\text{a}}_{\text{3}}}{\text{P}}{{\text{O}}_4}\left( {aq} \right) + 3{\text{L}}{{\text{i}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\left( {{\text{aq}}} \right) \to 2{\text{L}}{{\text{i}}_{\text{3}}}{\text{P}}{{\text{O}}_4}\left( s \right) + 3{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left( {aq} \right)[/tex]
Learn more:
1. Determine the balanced equation for the given reaction: https://brainly.com/question/2612756
2. Write a balanced equation for ammonia with copper oxide:https://brainly.com/question/1995521
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Redox reaction
Keywords: balanced equation, double displacement reaction, sodium, oxygen, lithium, phosphorous, Na3PO4, Li2SO4, Na2SO4, and Li3PO4.
