Respuesta :
Average = number of pages / time taken
= 1. 1/2 / 3 1/3
= 3/2 / 10/3
= 3/2 * 3 /10
= 9/20
Answer 9/20 pages per minute.
= 1. 1/2 / 3 1/3
= 3/2 / 10/3
= 3/2 * 3 /10
= 9/20
Answer 9/20 pages per minute.
Answer: The required average unit rate for reading is [tex]\dfrac{9}{20}[/tex] pages per minute.
Step-by-step explanation: Given that Sean is bookworm. On average, he reads [tex]1\dfrac{1}{2}[/tex] pages in [tex]3\dfrac{1}{3}[/tex] minute.
We are to find the average unit rate for reading the book.
We have
[tex]1\dfrac{1}{2}=\dfrac{3}{2},~~~3\dfrac{1}{3}=\dfrac{10}{3}.[/tex]
We will be using the UNITARY method to solve the problem.
We have
Number of pages read in [tex]\dfrac{10}{3}[/tex] minutes is
[tex]\dfrac{3}{2}.[/tex]
Therefore, the number of pages read in 1 minute is given by
[tex]\dfrac{\frac{3}{2}}{\frac{10}{3}}\\\\\\=\dfrac{3}{2}\times\dfrac{3}{10}\\\\\\=\dfrac{9}{20}.[/tex]
Thus, the required average unit rate for reading is [tex]\dfrac{9}{20}[/tex] pages per minute.
