The product of two numbers is done by multiplying a number with the other. The product of [tex](n - 1)[/tex] and [tex](n + 1)[/tex] is always equal to [tex]n^2 - 1[/tex]
The given parameters are:
[tex](n - 1)[/tex] and [tex](n + 1)[/tex]
Their product is:
[tex]Product = (n - 1) \times (n + 1)[/tex]
Expand
[tex]Product = n(n + 1) -1 (n + 1)[/tex]
Open brackets
[tex]Product = n^2 + n -n -1[/tex]
Evaluate like terms
[tex]Product = n^2 -1[/tex]
It should be noted that the given data is a representation of difference of two squares
Hence, the product of [tex](n - 1)[/tex] and [tex](n + 1)[/tex] is always equal to [tex]n^2 - 1[/tex]
Read more about difference of two squares at:
https://brainly.com/question/914765
