Respuesta :
12c^9 + 28c^7
first we find the GCF of 12 and 28.....thats gonna be 4
then, for the exponents.....take the smallest one...it is c^7
so we factor out 4c^7
4c^7(3c^2 + 7) <===
first we find the GCF of 12 and 28.....thats gonna be 4
then, for the exponents.....take the smallest one...it is c^7
so we factor out 4c^7
4c^7(3c^2 + 7) <===
Answer:
[tex]4*c^7*(3*c^2+7)[/tex]
Step-by-step explanation:
We want to see which common terms are in the polynomial. We can take out the small exponent of c and take out the common number term
The smallest exponent of c is 7 so according to the product rule, exponents of the same base are added to one another:
[tex]c^7(12*c^2+28)[/tex]
We can also see that dividing by 4 can get a smaller numbers and therefore 4 can be factored as well:
[tex]4*c^7*(3*c^2+7)[/tex]