Answer: The moles of HCl required to completely neutralize calcium hydroxide is 0.60 moles.
Explanation:
We are given:
Moles of calcium hydroxide = 0.30 moles
The chemical equation for the reaction of HCl with calcium hydroxide follows:
[tex]Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of calcium hydroxide reacts with 2 moles of HCl
So, 0.30 moles of calcium hydroxide will react with = [tex]\frac{2}{1}\times 0.30=0.60mol[/tex] of HCl
Hence, the moles of HCl required to completely neutralize calcium hydroxide is 0.60 moles.