Respuesta :
4 months because it decreases 2000 each year, and 1.5 hundred each month I think so
Answer: Hello mate!
we know that the model of the population is described with the function [tex]A(t) = A0e^{kt}[/tex] where A0 and k are constants, and t is time.
we know that five years ago, the population wass 10000 and now is 2000, if we set t = 0 five years ago then, and define t in years:
[tex]A(0) = 10000 = A0e^{k0} = A0[/tex], now we know the value of A0.
and [tex]A(5) = 10000e^{k5} = 2000[/tex]
[tex]e^{k5} = 2000/10000 = 0.2[/tex]
[tex]k5 = ln(0.2)[/tex]
[tex]k = ln(0.2)/5 = -0.32[/tex]
then the equation is:
[tex]A(t) = 10000e^{-0.32t}[/tex]
now we want to find the value of t where A(t) = 500 then:
[tex]A(t) = 500 = 10000e^{-0.32t}[/tex]
[tex]500/10000 = 0.05 = e^{-0.32t}[/tex]
[tex]ln(0.05)/-0.32 = t = 9.4[/tex]
But remember that we took t = 0 five years ago, then the event will ocurr in 9.4 - 5 = 4.4 years.