one car takes 2 minutes for once around
so in 1 minute it does a 1/2 around
.
second car takes 1 1/2 minutes for once around ( 1 1/2 = 3/2)
so in 1 minute it does 2/3 round
every minute the second car gains 2/3 -1/2 of the round
2/3 = 4/6, 1/2 = 3/6
4/6 - 3/6 = 1/6 of the track per minute
so every 6 minutes the faster car overtakes the slower car.
Answer:
6 minutes is the answer.
Step-by-step explanation:
One goes around the track in 2 minutes.
The other goes around the track in [tex]1\frac{1}{2}[/tex] or 1.5 minutes
WE will find the least common multiple of 2 and 1.5.
The LCM of 2 and 1.5 is 6.
That means in every 6 minutes, both the cars are at the same point.
We have to tell how often does the faster car pass the slower car. The answer is in 6 minutes.
