Answer: C. 2520
Step-by-step explanation:
Given digits: 0, 1, 2, 3, 4, 5, 6
Total number of digits=7
The number of ways, in which 5-digit numbers can be formed using the above digits if repetition of digits is not allowed is given by permutation:-
[tex]^7P_5=\frac{7!}{(7-5)!}\\\\=\frac{7\times6\times5\times4\times3\times2!}{2!}\\\\=\frac{5040}{2}\\=2520[/tex]
Hence, the number of 5 digit numbers can be formed with the given digits (if repetition is not allowed)=2520
