Respuesta :
Answer: 'Triangle ABC is similar to triangle EDC , because [tex]m\angle 2=m\angle 6[/tex] and [tex]m\angle 1=m\angle 5[/tex]
' is the correct option.
Step-by-step explanation:
Since, Here [tex]AB\parallel DE[/tex] and BD and AE are the transversals which cut these two parallel lines
Thus according to the figure,[tex]\angle 2= \angle 6[/tex] ( Because alternative interior angles made by the same transversal on two parallel lines are always equal)
Similarly, [tex]\angle 1=\angle 5[/tex]
Thus In triangles ABC and DCE,
[tex]\angle 2= \angle 6[/tex]
And, [tex]\angle 1=\angle 5[/tex]
thus If In two triangles two corresponding angles are equal, then they are similar to each other.
Therefore, [tex]\triangle ABC\sim \triangle EDC[/tex]
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