Answer:
1.847*10^24 photons
Explanation:
Generally, a photon has certain amount of energy which can be calculated using the equation below:
E = (h*c)/λ
Where:
E = energy of the a photon (J)
h = Planck's constant = 6.626*10^-34 (J.s)
c = speed of light = 299792458 (m/s)
λ = wavelength = 589 nm = 589*10^-9 m
Therefore:
E = (6.626*10^-34 * 299792458)/589*10^-9 = 3.373*10^-19 J
The energy of one photon is equivalent to 3.373*10^-19 J. Therefore, to find the number of photons in 623 kJ of energy, we have:
Number of photons = 623000/3.373*10^-19 = 1.847*10^24 photons
Thus, there are 1.847*10^24 photons in 623 kJ of energy.
Since the sodium lamp that contains 623 kJ of energy, there are [tex]1.85 \times 10^{22}[/tex] photons.
Given the following data:
To determine the amount of photons that are contained in a burst of yellow light (589 nm) from a sodium lamp, we would use Einstein's equation for photon energy:
Mathematically, Einstein's equation for photon energy is given by the formula:
[tex]E = hf = h\frac{v}{\lambda}[/tex]
Where:
Substituting the given parameters into the formula, we have;
[tex]E = \frac{6.626 \times 10^{-34}\times 3 \times 10^{8}}{589 \times 10^{-9}} \\\\E = \frac{1.99 \times 10^{-25}}{589 \times 10^{-9}}[/tex]
E = [tex]3.37 \times 10^{-17}[/tex] Joules
Since the sodium lamp that contains 623 kJ of energy, we would divide it by the maximum kinetic energy to get the number of photons:
[tex]Number\;of\;photon = \frac{623000}{3.37 \times 10^{-17}}[/tex]
Number of photons = [tex]1.85 \times 10^{22}[/tex] photons
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