Jinwon
Jinwon Jinwon
  • 12-09-2017
  • Mathematics
contestada

1/y - 1/x = 1/60
3y - 2x = 6
(Simultaneous question)

Respuesta :

musiclover10045
musiclover10045 musiclover10045
  • 12-09-2017

1y - 1/x = 1/60 = x*y =60 = x=60/y

3y - 2(60/y) = 6

3y^2-120=6y

3(y^2-40-2y) =0

y^2-40-2y=0

y = 7.4


3(7.4)-2x=6

22.2-2x = 6

2x = -16.2

x = -8.1



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