Respuesta :
2x² +8y = 121.5
8y = 121.5 - 2x²
and,
x²-8y = 121.5
-8y = 121.5 -x²
8y = x²-121.5
Now, equate the two 8y's
121.5-2x² = x² -121.5
-3x² = -121.5-121.5
-3x² = -243
3x² = 243
x² = 81
x = ±9
8y = 121.5 - 2x²
and,
x²-8y = 121.5
-8y = 121.5 -x²
8y = x²-121.5
Now, equate the two 8y's
121.5-2x² = x² -121.5
-3x² = -121.5-121.5
-3x² = -243
3x² = 243
x² = 81
x = ±9
The value of x from the given system of quadratic equations is 9.
Given the following data:
[tex]2x^2 + 8y = 121.5\\\\x^2 - 8y = 121.5[/tex]
To find the value of x, we would solve the system of quadratic equations by using the elimination method:
Adding the two system of quadratic equations together, we have:
[tex]2x^2 + x^2 + (8y - 8y) = 121.5 + 121.5\\\\3x^2 = 243\\\\x^2 = \frac{243}{3} \\\\x^2 = 81\\\\x = \sqrt{81}[/tex]
x = 9
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