Respuesta :

[tex] \frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x} [/tex] is given 
here , [tex] \frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x} [/tex] 
or, [tex] \frac{7x^{2} +x +2x-4 }{x(x-2)} = \frac{-4}{ x^{2} -2x} [/tex]
or,[tex] \frac{7 x^{2} +3x-4}{ x^{2} -2x} = \frac{-4}{ x^{2} -2x} [/tex]
or,7x²+3x-4=-4
or,7x²+3x=0
or,x(7x+3)=0
Either,x=0| Or,7x+3=0
                |or,7x=-3
                |or,x=[tex] \frac{-3}{7} [/tex]
So , the solution set is S={0,-[tex] \frac{3}{7} [/tex]}