Respuesta :

haneul
Set up an equation; let x represent the smaller number and x+1 is the larger number. x squared = x(x+1)+9. Solve to find the solution.
Hope that helped.

Answer:

-9 and -8

Step-by-step explanation:

We are given that

Product of two consecutive integers  is 9 less than the square of the smaller number .

We have to find two consecutive integers

Let x and x+1 are two consecutive integers

According to question

[tex]x(x+)=x^2-9[/tex]

Because x is smaller than x+1

[tex]x^2+x=x^2-9[/tex]

[tex]x^2+x-x^2=-9[/tex]

[tex]x=-9[/tex]

Substitute the value of x then we get

[tex]x+1=-9+1=-8[/tex]

Hence, the two consecutive integers are -9 and -8.