Respuesta :
Set up an equation; let x represent the smaller number and x+1 is the larger number. x squared = x(x+1)+9. Solve to find the solution.
Hope that helped.
Hope that helped.
Answer:
-9 and -8
Step-by-step explanation:
We are given that
Product of two consecutive integers is 9 less than the square of the smaller number .
We have to find two consecutive integers
Let x and x+1 are two consecutive integers
According to question
[tex]x(x+)=x^2-9[/tex]
Because x is smaller than x+1
[tex]x^2+x=x^2-9[/tex]
[tex]x^2+x-x^2=-9[/tex]
[tex]x=-9[/tex]
Substitute the value of x then we get
[tex]x+1=-9+1=-8[/tex]
Hence, the two consecutive integers are -9 and -8.