Respuesta :
A. p+l = 32 cm maka p = 32 - l
L = 240 cm
L = p x l
240 = 32-l x l
240 = 32l - l²
l²-32l+240 = 0
(l-12)(l-20) = 0
maka l = 12 atau l = 20
ambil saja lebarnya = 12 cm
maka p = 32-l = 32 - 12 = 20 cm
b. Keliling = 2(p+l) = 2 x 32 = 64 cm
c. Diagonal = √p²+l² = √20²+12² = √400+144 = √544 = √16x34 = 4√34 cm
L = 240 cm
L = p x l
240 = 32-l x l
240 = 32l - l²
l²-32l+240 = 0
(l-12)(l-20) = 0
maka l = 12 atau l = 20
ambil saja lebarnya = 12 cm
maka p = 32-l = 32 - 12 = 20 cm
b. Keliling = 2(p+l) = 2 x 32 = 64 cm
c. Diagonal = √p²+l² = √20²+12² = √400+144 = √544 = √16x34 = 4√34 cm
P and L : 12 and 20 cm
Perimeter : 64 cm
Diagonal = 4√34
Further explanation
The playground is a rectangular shape. There are several properties possessed by rectangular shapes, namely:
• 1. each angle is equal and is a right angle
• 2. the diagonals intersect and divide each other equally
• 3. sides facing the same length
There are two rectangular shapes namely square and rectangle
Square if all sides are the same length
The formula used in rectangular is:
• 1.Area
Rectangle
[tex]\large{\boxed{\bold{Area=w\:\times\:l}}}[/tex]
w = width
l = length
Square
[tex]\large{\boxed{\bold{area=a^2}}}[/tex]
a = length of side
• 2. perimeter
Rectangle
[tex]\large{\boxed{\bold{perimeter=2\times(w+l)}}}[/tex]
w = width
l = length
Square
[tex]\large{\boxed{\bold{perimeter=4\times\:a}}}[/tex]
a = length of side
P+L = 32 cm
Area = 240 cm²
Then
P = 32-L
Area = (32-L) x L
Area =32L-L²
240 = 32L-L²
-L²+32L-240=0
L²-32L+240 = 0
(L-12)(L-20)=0
L = 12 or L = 20
Then =P= 20 or 12
B)Perimeter= 2 x (P +L) = 2 x (12+20) = 64 cm
C) Diagonal
Phytagoras :
[tex]\rm diagonal=\sqrt{20^2+12^2}\\\\diagonal=\sqrt{400+144}\\\\diagonal=\sqrt{544}=4\sqrt{34}[/tex]
Learn more
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