In right triangle LMN are given the lenghts of two legs. You can find the value of [tex]\tan x[/tex] and [tex]\tan y[/tex] and then estimate the difference y-x.
1.
[tex]\tan x=\dfrac{LM}{LN}=\dfrac{14.1}{19.1}=\dfrac{141}{191},\\ \\x=\arctan \dfrac{141}{191}\approx 36.4^{\circ}.[/tex]
2.
[tex]\tan y=\dfrac{LN}{LM}=\dfrac{19.1}{14.1}=\dfrac{191}{141},\\ \\y=\arctan \dfrac{191}{141}\approx 53.6^{\circ}.[/tex]
Then
[tex]y-x=53.6^{\circ}-36.4^{\circ}=17.2^{\circ}.[/tex]
Answer: correct choice is D
