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If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? A.) 0.029 mol B.) 0.250 mol C.) 0.351 mol D.) 3.00 mol

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Mowens3
0.029 iss the answer. 

Answer: A.) 0.029

Explanation: To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}[/tex]

For sodium:

Mass of sucrose given = 10 g

Molar mass of sucrose [tex]C_{12}H_{22}O_{11}[/tex] = 342 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of sodium}=\frac{10g}{342g/mol}=0.029mol[/tex]

Thus the number of moles of sucrose available for this reaction will be 0.029.

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