Answer:
1 unit shorter
Step-by-step explanation:
By plotting the given points in the coordinate plane,
We get a rectangle ABCD having vertices,
A(-1,6), B (3,6), C (3,1), D (-1,1)
By the distance formula,
Shorter side or width of the rectangle,
[tex]AB=\sqrt{(3-(-1))^2+(6-6)^2}=\sqrt{4^2+0}=4\text{ unit}[/tex]
Longer side or length of the rectangle,
[tex]BC=\sqrt{(3-3)^2+(1-6)^2}=\sqrt{5^2}=5\text{ unit}[/tex]
The difference between length and width,
[tex]BC - AB = 5 - 4 = 1\text{ unit}[/tex]
Hence, the width of rectangle is 1 unit less than the length.
