A total of 1.1 × 10⁵Joules energy was dissipated by friction
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Further explanation
Let's recall Kinetic Energy Formula as follows:
[tex]Ek = \frac{1}{2}mv^2[/tex]
Ek = Kinetic Energy ( Joule )
m = mass of the object ( kg )
v = speed of the object ( m/s )
Let us now tackle the problem !
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Complete Questions:
A 66-kg skier starts from rest at the top of a 1200-m long trail which drops a total of 170 m from top to bottom. at the bottom, the skier is moving 11.0 m/s. How much energy was dissipated by friction?
Given:
mass of skier = m = 66 kg
height of trail = h = 170 m
velocity of skier = v = 11.0 m/s
Asked:
work done by friction = W = ?
Solution:
[tex]W = Ep - Ek[/tex]
[tex]W = mgh - \frac{1}{2}mv^2[/tex]
[tex]W = 66(9.8)(170) - \frac{1}{2}(66)(11.0)^2[/tex]
[tex]W = 109956 - 3993[/tex]
[tex]W = 105963[/tex] [tex]\texttt{ J}[/tex]
[tex]W \approx 1.1 \times 10^5 \texttt{ J}[/tex]
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Conclusion:
A total of 1.1 × 10⁵ Joules energy was dissipated by friction
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Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
- Newton's Law of Motion: https://brainly.com/question/10431582
- Example of Newton's Law: https://brainly.com/question/498822
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Answer details
Grade: High School
Subject: Physics
Chapter: Dynamics
