The k a for hypochlorous acid, hocl, is 3.0 × 10-8 at 25°c. calculate the pk b for hypochlorous anions.

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11-10-2017
Chemistry

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The k a for hypochlorous acid, hocl, is 3.0 × 10-8 at 25°c. calculate the pk b for hypochlorous anions.

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Kalahira Kalahira · Answer 1 · 2017-10-21T14:36:52+02:00

Kalahira Kalahira

21-10-2017

HClO <-----> H+ + ClO- at equilibrium [HClO]= 0.015-x [H+] = [ClO-]= x 3.0 x 10^-8 = x^2/ 0.015-x x = 2.1 x 10^-5 % ionization = 2.1 x 10^-5 x 100/ 0.015=0.14

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BarrettArcher BarrettArcher · Answer 2 · 2019-04-18T10:01:17+02:00

Answer : The value of [tex]pK_b[/tex] for hypochlorous anion is, 6.47

Explanation :

As we know that,

[tex]pK_a+pK_b=pK_w\\\\pK_a+pK_b=14\\\\pK_b=14-pK_a\\\\pK_b=14-(-\log K_a)\\\\pK_b=14+\log (K_a)[/tex]

Now put the value of [tex]K_a[/tex] in this expression, we get the value of [tex]pK_b[/tex]

[tex]pK_b=14+\log (3.0\times 10^{-8})[/tex]

[tex]pK_b=14+\log 3-8[/tex]

[tex]pK_b=6.47[/tex]

Therefore, the value of [tex]pK_b[/tex] for hypochlorous anion is, 6.47