Respuesta :
Answer : The correct option is, 55.92 %
Solution : Given,
Molar mass of [tex]Na_2SO_4.10H_2O[/tex] = 322 g/mole
Molar mass of water = 18 g/mole
The mass of [tex]10H_2O[/tex] = [tex]10\times 18=180g[/tex]
Now we have to calculate the percent by mass of water in [tex]Na_2SO_4.10H_2O[/tex]
Formula used :
[tex]\text{Percent by mass of water}=\frac{\text{Mass of}10H_2O}{\text{Mass of }Na_2SO_4.10H_2O}\times 100=\frac{180g}{322g}\times 100=55.92\%[/tex]
Therefore, the percent by mass of water in [tex]Na_2SO_4.10H_2O[/tex] is, 55.92 %
