Respuesta :
20 meters per second. I use the formula V^2=V0^2 + 2*a*d. a is acceleration and d is distance.
Answer:
Final speed of the car, v = 20 m/s
Explanation:
It is given that,
Initial speed of the car, u = 8 m/s
Acceleration of the car, [tex]a=3\ m/s^2[/tex]
Let v is the speed of the car after it has accelerated for 56 meters. It can be calculated suing the third equation of motion. It is given by :
[tex]v^2-u^2=2ad[/tex]
[tex]v^2=u^2+2ad[/tex]
[tex]v^2=(8)^2+2\times 3\times 56[/tex]
v = 20 m/s
So, the car is moving after it has accelerated for 56 meters is 20 m/s. Hence, this is the required solution.
