12)
b)
y=mx+d
you know m=3/2
->
y=(3/2)x+b
for the complete definition of the line you need to calculate b, for this insert the given point (-4,-2) into x and y which the line passes:
-2=(3/2)*-4+b
-2=-6+b
4=b
so your line is y=(3/2)x+4
c)
y=mx+d
you have two points, so you can calculate the slope:
m=(y2-y1)/(x2-x1)=
(-5-3)/(2-(-2))=
-8/4=-2=m
->y=-2x+b
-> insert (2,-5) to calculate b
-5=-2*2+b
-5=-4+b
-1=b
->
y=-2x-1
13)
two lines are parallel if they have the same slope-> you know m=-2 from y=-2x+3
calculate b by inserting the point (1,3) it passes through
y=-2*x+b
3=-2*1+b
3=-2+b
5=b
y=-2x+5
