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Consider a sign suspended on a boom that is supported by a cable, as shown. What is the proper equation to use for finding the net force in the y direction?
Fnety = (FT)(sin 32°) + Fg
Fnety = (FT)(sin 32°) – Fg
Fnety = (FT)(cos 32°) + Fg
Fnety = (FT)(cos 32°) – Fg

Respuesta :

Fnety = (FT)(sin 32°) – Fg Or the answer B, I checked it.

Answer:

B: Fnety = (FT)(sin 32°) – Fg

Explanation:

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