15 POINTS!!!!!!! What is the equation of the line in slope-intercept form? Line on a coordinate plane. Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.

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Answer:

[tex]y=\frac{4}{3}x+4[/tex] is the equation of line in slope intercept form.

Step-by-step explanation:

Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.

First ordered pair: (-3,0)

Second ordered pair: (0,4)

We have two points and need to find equation of line in slope intercept form

[tex]\text{Slope (m)}=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\text{Slope (m)}=\dfrac{4-0}{0-(-3)}=\dfrac{4}{3}[/tex]

y-intercept, when x=0 , (0,4)

Equation of line in slope intercept form:

y=mx+b

where, [tex]m=\frac{4}{3}[/tex] and b=4

Required equation:

[tex]y=\frac{4}{3}x+4[/tex]

Thus, [tex]y=\frac{4}{3}x+4[/tex] is the equation of line in slope intercept form.

Answer:

1/5

Step-by-step explanation:

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