For each question below, identify if first number is divisible by the second number, and if so, the reason why.
Is 26 divisible by 2?

A.
No

B.
Yes, because 2 + 6 = 8 and 8 is divisible by 2.

C.
Yes, because the last digit is 6, which is divisible by 2.


Is 216 divisible by 3?

A.
No

B.
Yes, because the sum of 2 + 1 + 6 = 9, which is divisible by 3.

C.
Yes, because the last digit is 6, which is divisible by 3.


Is 40,100 divisible by 10?

A.
No

B.
Yes, because there is a 10 in the number.

C.
Yes, because the last digit of the number is 0.


Is 318 divisible by 9?

A.
No

B.
Yes, because the last two digits are 18, which is divisible by 9.

C.
Yes, because the sum of the digits is 3 + 1 + 8 = 12, which is divisible by 3, and all numbers divisible by 3 are divisible by 9.


Is 87,235 divisible by 5?

A.
No

B.
Yes, because the last digit of the number is 5.

C.
Yes, because the sum of the digits is 8 + 7 + 2 + 3 + 5 = 25, which is divisible by 5.


Is 43,121 divisible by 3?

A.
No

B.
Yes, because the last two digits of the number are 21, which is divisible by 3.

C.
Yes, because the sum of the digits is 4 + 3 + 1 + 2 + 1 = 11, which is divisible by 3.


Is 1, 112 divisible by 5?

A.
No

B.
Yes, because the last digit in the number is 2.

C.
Yes, because 1 + 1 + 1 + 2 = 5, which is divisible by 5.


Is 10,000,058 divisible by 10?

A.
No

B.
Yes, because the last digit is an even number.

C.
Yes, because the first two digits of the number are 10.


Is 94,032 divisibly by 9?

A.
No

B.
Yes, because the sum of the digits is 9 + 4 + 0 + 3 + 2 = 18, which is divisible by 9.

C.
Yes, because the value of the first digit is 9, which is divisible by 9.


Is 201,086 divisible by 2

A.
No

B.
Yes, because all of the digits are even numbers.

C.
Yes, because the last digit in the number is 6, which is an even number.