Respuesta :
The acceleration which the 1300-kg Coupe experiences while skidding to a stop is [tex]8.33 m/s^2[/tex]
What is acceleration?
Acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities as it has both magnitude and direction.
It is given by
[tex]a = \frac{v_{i} - v_{f} }{t}[/tex]
Where,
[tex]a =[/tex] average acceleration
[tex]v_{f} =[/tex] final velocity
[tex]v_i[/tex] = starting velocity
[tex]t[/tex] = elapsed time
What is coefficient of friction?
Coefficient of friction is defined as the ratio between friction force and normal force.
Given:
Coefficient of friction[tex]= 0.85[/tex]
Mass of Dawson’s 1985 Ford Coupe [tex]= 1300 Kg[/tex]
Since,
The normal force is,
[tex]F_n = mg\\F_n = 1300*9.8\\F_n = 12740 N[/tex]
Coefficient of friction is given by
Coefficient of friction = friction force /normal force
Friction force= Coefficient of friction*Normal force
[tex]F_f = 0.85*12740\\F_f = 10829 N[/tex]
To calculate acceleration, we have
[tex]a = (F_f) / m\\a = \frac{10829}{1300} \\a = 8.33 m/s^2[/tex]
Thus, the acceleration is [tex]8.33 m/s^2[/tex]
To learn more about acceleration here
https://brainly.com/question/2303856
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