Kc is simply the ratio of the concentration of the product over the reactant, that is:
Kc = [NO2]^2 / [N2O4] = 1.46
Now since the overall equation or concentration is multiplied by 5, therefore:
{[NO2]^2 / [N2O4]}^5 = 1.46^5 =>
Kc = 6.63
Answer:- Kc = 6.63
Solution:- First given equation is:
[tex]N_2O_4(g)\rightleftharpoons 2NO_2(g)[/tex]
The equilibrium expression for this equation is written as:
[tex]Kc=\frac{[NO_2]^2}{[N_2O_4]}[/tex]
The second given equation is:
[tex]5N_2O_4(g)\rightleftharpoons 10NO_2(g)[/tex]
The equilibrium expression for this equation is written as:
[tex]Kc^'=\frac{[NO_2]^1^0}{[N_2O_4]^5}[/tex]
Comparing these two expressions, to get this second expression from the first one, we need to do the fifth power of first equilibrium expression.
Hence, [tex]Kc^'=(Kc)^5[/tex]
Plug in the value of Kc in it from first expression, [tex]Kc^'=(1.46)^5[/tex]
[tex]Kc^'[/tex] = 6.63
So, the Kc of second equation is 6.63.
