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The correct answer to your question and how to solve it is
The relation between wavelength (λ)and the frequency of electromagnetic oscillation (f) is described by the following expression: λ=c/f, where c–is the speed of light in vacuum = 3*10^8 m/s
Derive f from above: f = c/λ.How to Calculate: λ=890nm = 890*10^-9m = 8.9*10^-7m
f =3*10^8m/s Divided by 8.9*10^-7m = 0.34*10^15 s-1=3.4*10^14 s-1
So your Answer is: The frequency of radiation of wavelength 890 nm is 3.4*10^14s-1
The relation between wavelength (λ)and the frequency of electromagnetic oscillation (f) is described by the following expression: λ=c/f, where c–is the speed of light in vacuum = 3*10^8 m/s
Derive f from above: f = c/λ.How to Calculate: λ=890nm = 890*10^-9m = 8.9*10^-7m
f =3*10^8m/s Divided by 8.9*10^-7m = 0.34*10^15 s-1=3.4*10^14 s-1
So your Answer is: The frequency of radiation of wavelength 890 nm is 3.4*10^14s-1
The frequency of radiation of the given wavelength is [tex]3.125 \times 10^{14} \ Hz[/tex]
The given parameters:
- wavelength of the radiation, λ = 960 nm
The frequency of radiation of the given wavelength is calculated as follows;
[tex]c = f \lambda \\\\[/tex]
where;
c is the speed of light = 3 x 10⁸ m/s
f is the frequency of the radiation
[tex]f = \frac{c}{\lambda} \\\\f = \frac{3\times 10^8}{960 \times 10^{-9} } \\\\f = 3.125 \times 10^{14} \ Hz[/tex]
Thus, the frequency of radiation of the given wavelength is [tex]3.125 \times 10^{14} \ Hz[/tex].
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