The formula for Kw is:
Kw= [H]*[OH]
where [H] and [OH] are
concentrations
We are given the pH so we can calculate the [H]
concentration from the formula:
pH=-log[H]
7.43 = -log[H]
[H] = 3.715x10^-8 M
In neutral solution, [H] = [OH], therefore:
[OH]= 3.715x10^-8 M
Calculating Kw:
Kw = (3.715x10^-8)*( 3.715x10^-8)
Kw = 1.38 x 10^-15
The value of the ionic product of water at neutral pH of 7.43 has been 1.38 [tex]\rm \times\;10^-^1^5[/tex] [tex]\rm mol^2\;dm^-^6[/tex].
[tex]\rm K_w[/tex] has the ionic product of water and varies at different temperatures.
The ionic product can be given as:
[tex]\rm K_w\;=\;[H^+]\;[OH^-][/tex]
The hydrogen ion concentration at pH 7.43 will be:
pH = -log [Hydrogen ion concentration]
7.43 = -log [Hydrogen ion concentration]
Hydrogen ion concentration = 3.715 [tex]\rm \times\;10^-^8[/tex] M
At neutral pH, the hydrogen ion concentration is equal to hydroxide ion concentration.
[tex]\rm K_w[/tex] = 3.715 [tex]\rm \times\;10^-^8[/tex] [tex]\times[/tex] 3.715 [tex]\rm \times\;10^-^8[/tex] M
[tex]\rm K_w[/tex] = 1.38 [tex]\rm \times\;10^-^1^5[/tex] [tex]\rm mol^2\;dm^-^6[/tex].
The value of the ionic product of water at neutral pH of 7.43 has been 1.38 [tex]\rm \times\;10^-^1^5[/tex] [tex]\rm mol^2\;dm^-^6[/tex].
For more information about ionic product, refer to the link:
https://brainly.com/question/12164558
