Answer:
[tex]\frac{1}{4}[/tex]
Step-by-step explanation:
In order to calculate the probability of Ming winning, you just have to multiply both probabilities of obtaining an even number when rolling the dice, and the probability of heads appearing when tossing the coin.
[tex]Probability.Dice=\frac{3}{6}[/tex]
There are 6 numbers in a dice, and there are 3 even numbers, so the probability is 3 out of 6.
The probability of heads appearing when tossing a coin is just 1 out of two.
[tex]Coin.probability=\frac{1}{2}[/tex]
So the probability of two independent events happening is evaluated by multiplying both probabilities, this would be:
[tex]Probability of both=(\frac{3}{6})(\frac{1}{2})\\Probability of both=(\frac{3}{12})\\Probability of both=(\frac{1}{4})[/tex]
