How many grams of glucose are in 175 mL of a 5.50% (m/v) glucose solution?

1. 5.50% m/v means that the solution contains 5.50% of the volume measured in grams

so in 165mL you will have 5.5%*165 = 9.075g

2. 18.5% v/v means 18.5% of the total volume is methyl alcohol

so in 1.87L you will have 18.5%*1.87 = 0.35L of methyl alcohol.

3. This one works backwards. If 32.1 g is 6.00%, what is 100%?

100% = 32.1/0.06 = 535 mL

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RomeliaThurston RomeliaThurston · Answer 2 · 2019-08-16T12:52:07+02:00

Answer: The amount of glucose present in 175 mL of solution is 9.625 grams.

Explanation:

We are given:

5.50 % (m/v) glucose solution. This means that 5.50 grams of glucose is present in 100 mL of volume.

To calculate the amount of glucose in 175 mL of volume, we apply unitary method, we get:

In 100 mL of volume, the amount of glucose present is 5.50 g.

So, in 175 mL of volume, the amount of glucose present is [tex]\frac{5.50g}{100mL}\times 175=9.625g[/tex]

Hence, the amount of glucose present in 175 mL of solution is 9.625 grams.