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Write complete ionic equation to show the reaction of aqueous hg2(no3)2 with aqueous sodium chloride to form solid hg2cl2 and aqueous sodium nitrate. express your answer as a chemical equation. identify all of the phases in your answer.

Respuesta :

Answer: Hg2(NO3)2 + 2 NaCl --------> Hg2Cl2 + 2 NaNO3 Hg2+2 + 2NO3-1 + 2Na+ Cl- ----> Hg2Cl

First we start with our molecular equation to ensure all atoms are balanced in order to maintain the law of conservation of mass.

[tex]Hg_2(NO_3)_2_(_a_q_) + NaCl_(_a_q_) \implies Hg_2Cl_2_(_s_) + NaNO_3_(_a_q_)[/tex].

The equation is unbalanced since we have 1 Cl atom on left hand side as opposed to 2 on the right hand side and we have 2 [tex]NO_3[/tex] molecules on left hand side and 1 on the right hand side. So we add a coefficient of 2 on  both the [tex]NaCl[/tex] and [tex]NaNO_3[/tex]

[tex]Hg_2(NO_3)_2_(_a_q_) + 2NaCl_(_a_q_) \implies Hg_2Cl_2_(_s_) + 2NaNO_3_(_a_q_)[/tex]

The reaction occurs between solutes that are soluble in water to give a solid as a precipitate. So the complete ionic equation will show the soluble compounds in their dissociated states as ions in water and the insoluble compound as a solid.

[tex]2Hg^+_(_a_q_) + 2NO_3^-_(_a_q_) + 2Na^+_(_a_q_) + 2Cl^- _(_a_q_) \implies Hg_2Cl_2_(_s_) + 2Na^+_(_a_q_) + 2NO_3^-_(_a_q_)[/tex]