Respuesta :

Is this i as in the imaginary number?
If so:
-2*8(i²)
As you should know i² = -1
= -16(-1)
= 16

Answer:

The given expression is (-2 i)(8 i)

                                = (-2) × (8) (i)× (i)

                                 = -16 i²

                              as, i²= -1  [∴ i =√-1 so i× i=i²=√-1 × √-1≠ [tex]\sqrt{-1\times-1}[/tex] but = [tex]-\sqrt{-1\times-1}[/tex]=-1 ]

                                 = -16  × (-1)

                                 = 16